Matematika Sekolah Menengah Atas Tugas Matematika Sederhanakan 2.³√x²√x⁴√x ​
3.(√x²√y3/x¹/²√y³)³ sederhanakan

Tugas Matematika Sederhanakan 2.³√x²√x⁴√x ​
3.(√x²√y3/x¹/²√y³)³ sederhanakan

Jawab:

2. [tex]\sqrt[3]{x^{2} }\sqrt{x^{4} } \sqrt{x}[/tex]

  = [tex]\sqrt[3]{x^{2} }x^{2} \sqrt{x}[/tex]

  = [tex]\sqrt[6]{x^{4} }x^{2} \sqrt[6]{x^{3} }[/tex] ⇒menggunakan rumus [tex]\sqrt[n]{a}=\sqrt[mn]{a^{m} }[/tex]

  = [tex]\sqrt[6]{x^{4} . x^{3} } x^{2}[/tex]

  = [tex]\sqrt[6]{x^{7} }x^{2}[/tex]

  = [tex]x\sqrt[6]{x} x^{2}[/tex]

  =[tex]x^{3} \sqrt[6]{x}[/tex]

3. [tex](\frac{\sqrt{x^{2} }-\sqrt{y.3} }{\frac{x^{1} }{\sqrt{y^{3} } } } )^{3}[/tex]

= [tex](\frac{x-\sqrt{3y} }{\frac{x }{\sqrt{y^{3} } } } )^{3}[/tex]

= [tex](\frac{(x-\sqrt{3y})\sqrt{y^{3} } }{x} )^{3}[/tex]

= [tex](\frac{(x-\sqrt{3y})y\sqrt{y } }{x} )^{3}[/tex]

= [tex](\frac{xy\sqrt{y}-\sqrt{3y^{2}y } }{x})^{3}[/tex]

= [tex](\frac{xy\sqrt{y}-\sqrt{3}y.y }{x})^{3}[/tex]

= [tex](\frac{xy\sqrt{y}-\sqrt{3}y^{2} }{x})^{3}[/tex]

= [tex]\frac{(xy\sqrt{y}-\sqrt{3}y^{2})^{3} }{x^{3} }[/tex]

= [tex]\frac{x^{3}y^{4}\sqrt{y} - 3\sqrt{3}x^{2} y^{5}+9xy^{5}\sqrt{y}-3\sqrt{3}y^{6}}{x^{3} }[/tex]

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